yazyj
91AA9189-6BC2-4149-85F6-2158879A552E.jpeg 

How to get L? And what is your thought process for this? and how Long should I take to solve this 3mark question? 
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yazyj
B79B9552-BE82-4DD7-8E07-F4F0074378D4.jpeg  4402BBBC-BE26-4C92-AED3-0F212AD45481.jpeg

For the Q1biv, C, can this intermediate be accepted?

  931DAAC6-A0F4-40F3-B71F-87AF84194BFD.jpeg

  FD6D0F8D-C632-48F0-8E58-D531A32C65D4.jpeg

This is the answer’s intermediate.   
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BedokFunlandJC

yazyj wrote:
B79B9552-BE82-4DD7-8E07-F4F0074378D4.jpeg  4402BBBC-BE26-4C92-AED3-0F212AD45481.jpeg

For the Q1biv, C, can this intermediate be accepted?

  931DAAC6-A0F4-40F3-B71F-87AF84194BFD.jpeg

  FD6D0F8D-C632-48F0-8E58-D531A32C65D4.jpeg

This is the answer’s intermediate.   

 

Your answer is wrong, because this question is testing you to see if you know that C-I bond is weaker hence more readily cleaved compared to C-Cl bond.

A similar question would be, if 1 mol of acyl halide reacted with 1 mol of a hydroxylamine (ie. alcohol and amine group both present), would you get ester or amide?

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BedokFunlandJC
yazyj wrote:
91AA9189-6BC2-4149-85F6-2158879A552E.jpeg 

How to get L? And what is your thought process for this? and how Long should I take to solve this 3mark question? 


Based on M, L is obviously (CH3)2CHCH2Br, an alkyl bromide electrophile that reacts with Lewis acid catalyst FeBr3 to generate the (CH3)2CHCH2+ electrophile attacked by the benzene ring in an electrophilic aromatic substitution reaction. (In actuality, carbocation rearrangement would occur, but since that is beyond the H2 syllabus and not mentioned in the question, ignore it).

To obtain structures of L and N and P, give yourself 3 minutes. An approximate guide is 1 min (or less) per mark.
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